Tidy up code and add second part of exercise 4.42
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;; Exercise 4.42
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(define (fathers-daughters)
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;; Optimisation. Put everything we already know in a table. Each
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;; row is father, yacht, daughter.
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(define father car)
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(define yacht cadr)
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(define daughter caddr)
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(define (lookup-daughter f fathers)
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(daughter (assq f fathers)))
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(define (lookup-yacht f fathers)
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(yacht (assq f fathers)))
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(define (lookup-father d fathers)
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(cond ((null? fathers) false)
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((eq? d (daughter (car fathers)))
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(car (car fathers)))
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(else (lookup-father d (cdr fathers)))))
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(define (fathers-daughters mary)
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(define first-row car)
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(define rest-rows cdr)
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(define (daughter father)
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(caddr (assq father fathers)))
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(define (yacht father)
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(cadr (assq father fathers)))
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(define (father daughter)
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(define (loop f)
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(cond ((null? f) false)
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((eq? daughter (caddr (first-row f)))
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(car (first-row f)))
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(else (loop (rest-rows f)))))
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(loop fathers))
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;; Optimisation. Put everything we already know in a table. Each
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;; row is father, yacht, daughter.
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(define fathers
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(list
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(list 'moore 'lorna 'mary)
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(list 'hood 'gabrielle 'melissa)
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(list 'downing 'melissa (amb 'lorna 'gabrielle 'rosalind))
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(list 'hall 'rosalind (amb 'lorna 'gabrielle))
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(list 'parker 'mary (amb 'lorna 'gabrielle 'rosalind))))
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(if (eq? mary 'moore)
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;; Mary's surname is Moore
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(list
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(list 'moore 'lorna 'mary)
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(list 'hood 'gabrielle 'melissa)
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(list 'downing 'melissa (amb 'lorna 'gabrielle 'rosalind))
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(list 'hall 'rosalind (amb 'lorna 'gabrielle))
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(list 'parker 'mary (amb 'lorna 'gabrielle 'rosalind)))
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;; Mary's surname is unkonwn
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(list
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(list 'moore 'lorna (amb 'mary 'gabrielle 'rosalind))
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(list 'hood 'gabrielle 'melissa)
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(list 'downing 'melissa (amb 'mary 'lorna 'gabrielle 'rosalind))
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(list 'hall 'rosalind (amb 'mary 'lorna 'gabrielle))
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(list 'parker 'mary (amb 'lorna 'gabrielle 'rosalind)))))
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(require (distinct? (list (lookup-daughter 'moore fathers)
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(lookup-daughter 'hood fathers)
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(lookup-daughter 'downing fathers)
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(lookup-daughter 'hall fathers)
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(lookup-daughter 'parker fathers))))
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(require (distinct? (list (daughter 'moore)
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(daughter 'hood)
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(daughter 'downing)
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(daughter 'hall)
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(daughter 'parker))))
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;; Gabrielle's father owns the yacht named after parker's daughter
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(require (eq? (lookup-yacht (lookup-father 'gabrielle fathers) fathers)
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(lookup-daughter 'parker fathers)))
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(require (eq? (yacht (father 'gabrielle))
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(daughter 'parker)))
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fathers)
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;; Output
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;;; Amb-Eval input:
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(fathers-daughters 'moore)
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;;; Starting a new problem
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;;; Amb-Eval value:
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1
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((moore lorna mary) (hood gabrielle melissa) (downing melissa lorna) (hall rosalind gabrielle) (parker mary rosalind))
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;;; Amb-Eval input:
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try-again
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;;; There are no more values of
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3
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(fathers-daughters (quote moore))
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;; Lorna's father must be Colonel Downing.
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;; If we don't assume that Mary's surname is Moore:
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(fathers-daughters false)
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;;; Starting a new problem
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;;; Amb-Eval value:
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1
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((moore lorna mary) (hood gabrielle melissa) (downing melissa lorna) (hall rosalind gabrielle) (parker mary rosalind))
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;;; Amb-Eval input:
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try-again
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;;; Amb-Eval value:
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5
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((moore lorna gabrielle) (hood gabrielle melissa) (downing melissa rosalind) (hall rosalind mary) (parker mary lorna))
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;;; Amb-Eval input:
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try-again
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;;; There are no more values of
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10
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(fathers-daughters false)
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;; Lorna's father is either Colonel Downing or Dr Parker
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