Post: Advent of code day 21

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Jez Cope 2017-12-24 19:20:44 +00:00
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[Today's challenge](http://adventofcode.com/2017/day/20) finds us simulating the movements of particles in space.
[→ Full code on GitHub](https://github.com/jezcope/aoc2017/blob/master/19-a-series-of-tubes.rs)
[→ Full code on GitHub](https://github.com/jezcope/aoc2017/blob/master/20-particle-swarm.py)
!!! commentary
Back to Python for this one, another relatively straightforward simulation, although it's easier to calculate the answer to part 1 than to simulate.

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---
title: "Fractal Art — Python — #adventofcode Day 21"
description: "In which I make beautiful ASCII art."
slug: day-21
date: 2017-12-24T19:21:01+00:00
tags:
- Technology
- Learning
- Advent of Code
- Python
series: aoc2017
---
[Today's challenge](http://adventofcode.com/2017/day/21) asks us to assist an artist building fractal patterns from a rulebook.
[→ Full code on GitHub](https://github.com/jezcope/aoc2017/blob/master/21-fractal-art.md)
!!! commentary
Another fairly straightforward algorithm: the really tricky part was breaking the pattern up into chunks and rejoining it again. I could probably have done that more efficiently, and would have needed to if I had to go for a few more iterations and the grid grows with every iteration and gets big fast.
Still behind on the blog posts…
```python
import fileinput as fi
from math import sqrt
from functools import reduce, partial
import operator
INITIAL_PATTERN = ((0, 1, 0), (0, 0, 1), (1, 1, 1))
DECODE = ['.', '#']
ENCODE = {'.': 0, '#': 1}
concat = partial(reduce, operator.concat)
def rotate(p):
size = len(p)
return tuple(tuple(p[i][j] for i in range(size))
for j in range(size - 1, -1, -1))
def flip(p):
return tuple(p[i] for i in range(len(p) - 1, -1, -1))
def permutations(p):
yield p
yield flip(p)
for _ in range(3):
p = rotate(p)
yield p
yield flip(p)
def print_pattern(p):
print('-' * len(p))
for row in p:
print(' '.join(DECODE[x] for x in row))
print('-' * len(p))
def build_pattern(s):
return tuple(tuple(ENCODE[c] for c in row)
for row in s.split('/'))
def build_pattern_book(lines):
book = {}
for line in lines:
source, target = line.strip().split(' => ')
for rotation in permutations(build_pattern(source)):
book[rotation] = build_pattern(target)
return book
def subdivide(pattern):
size = 2 if len(pattern) % 2 == 0 else 3
n = len(pattern) // size
return (tuple(tuple(pattern[i][j] for j in range(y * size, (y + 1) * size))
for i in range(x * size, (x + 1) * size))
for x in range(n)
for y in range(n))
def rejoin(parts):
n = int(sqrt(len(parts)))
size = len(parts[0])
return tuple(concat(parts[i + k][j] for i in range(n))
for k in range(0, len(parts), n)
for j in range(size))
def enhance_once(p, book):
return rejoin(tuple(book[part] for part in subdivide(p)))
def enhance(p, book, n, progress=None):
for _ in range(n):
p = enhance_once(p, book)
return p
book = build_pattern_book(fi.input())
intermediate_pattern = enhance(INITIAL_PATTERN, book, 5)
print("After 5 iterations:", sum(sum(row) for row in intermediate_pattern))
final_pattern = enhance(intermediate_pattern, book, 13)
print("After 18 iterations:", sum(sum(row) for row in final_pattern))
```