reverting to the original colors in the text
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@ -199,12 +199,12 @@ how would we read what those literal shorts mean?
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we can read each of the colors vertically, from left to right. therefore:
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* color0 would have: red: 2, green: 1, blue: 1 (#221111 in hex color notation, brown)
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* color1 would be red: e, green: e, blue: e (#eeeeee in hex color notation, white)
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* color2 would be red: e, green: b, blue: 2 (#eebb22 in hex color notation, amber)
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* color3 would be red: f, green: 8, blue: e (#ff88ee in hex color notation, pink)
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* color0, a dark purple, would have: red: 2, green: 0, blue: 2 (#220022 in hex color notation)
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* color1, magenta, would have: red: c, green: 1, blue: c (#cc11cc in hex color notation)
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* color2, a light pink, would have: red: e, green: c, blue: e (#eeccee in hex color notation)
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* color3, a dark red, would have: red: 9, green: 0, blue: 5 (#990055 in hex color notation)
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if we run the program now we'll see a brown screen, instead of black as what we had before.
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if we run the program now we'll see a dark purple screen (color0), instead of black as what we had before.
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try changing the values of color0, i.e. the first column, and see what happens :)
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