mu/subx/010core.cc

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//:: simulated x86 registers; just a subset
//: assume segment registers are hard-coded to 0
//: no floating-point, MMX, etc. yet
:(before "End Types")
enum {
EAX,
ECX,
EDX,
EBX,
ESP,
EBP,
ESI,
EDI,
NUM_INT_REGISTERS,
};
union reg {
int32_t i;
uint32_t u;
};
:(before "End Globals")
reg Reg[NUM_INT_REGISTERS] = { {0} };
uint32_t EIP = 0;
:(before "End Reset")
bzero(Reg, sizeof(Reg));
EIP = 0;
//:: simulated flag registers; just a subset that we care about
:(before "End Globals")
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bool SF = false; // sign flag
bool ZF = false; // zero flag
bool OF = false; // overflow flag
:(before "End Reset")
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SF = ZF = OF = false;
//: how the flag registers are updated after each instruction
:(before "End Includes")
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// Combine 'arg1' and 'arg2' with arithmetic operation 'op' and store the
// result in 'arg1', then update flags.
// beware: no side-effects in args
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#define BINARY_ARITHMETIC_OP(op, arg1, arg2) { \
/* arg1 and arg2 must be signed */ \
int64_t tmp = arg1 op arg2; \
arg1 = arg1 op arg2; \
trace(2, "run") << "storing 0x" << HEXWORD << arg1 << end(); \
SF = (arg1 < 0); \
ZF = (arg1 == 0); \
OF = (arg1 != tmp); \
}
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// Combine 'arg1' and 'arg2' with bitwise operation 'op' and store the result
// in 'arg1', then update flags.
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#define BINARY_BITWISE_OP(op, arg1, arg2) { \
/* arg1 and arg2 must be unsigned */ \
arg1 = arg1 op arg2; \
trace(2, "run") << "storing 0x" << HEXWORD << arg1 << end(); \
SF = (arg1 >> 31); \
ZF = (arg1 == 0); \
OF = false; \
}
//:: simulated RAM
:(before "End Globals")
vector<uint8_t> Mem;
uint32_t End_of_program = 0;
:(before "End Reset")
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Mem.clear();
Mem.resize(1024);
End_of_program = 0;
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:(before "End Includes")
// depends on Mem being laid out contiguously (so you can't use a map, etc.)
// and on the host also being little-endian
#define SET_WORD_IN_MEM(addr, val) *reinterpret_cast<int32_t*>(&Mem.at(addr)) = val;
//:: core interpreter loop
:(scenario add_imm32_to_eax)
# In scenarios, programs are a series of hex bytes, each (variable-length)
# instruction on one line.
#
# x86 instructions consist of the following parts (see cheatsheet.pdf):
# opcode ModR/M SIB displacement immediate
# instruction mod, reg, Reg/Mem bits scale, index, base
# 1-3 bytes 0/1 byte 0/1 byte 0/1/2/4 bytes 0/1/2/4 bytes
05 0a 0b 0c 0d # add 0x0d0c0b0a to EAX
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# All hex bytes must be exactly 2 characters each. No '0x' prefixes.
+load: 1 -> 05
+load: 2 -> 0a
+load: 3 -> 0b
+load: 4 -> 0c
+load: 5 -> 0d
+run: add imm32 0x0d0c0b0a to reg EAX
+run: storing 0x0d0c0b0a
:(code)
// helper for tests: load a program into memory from a textual representation
// of its bytes, and run it
void run(string text_bytes) {
// Begin run() For Scenarios
//? cerr << text_bytes << '\n';
load_program(text_bytes, 1); // tests always assume a starting address of 1
EIP = 1; // preserve null pointer
while (EIP < End_of_program)
run_one_instruction();
}
// skeleton of how x86 instructions are decoded
void run_one_instruction() {
uint8_t op=0, op2=0, op3=0;
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trace(2, "run") << "inst: 0x" << HEXWORD << EIP << end();
switch (op = next()) {
case 0xf4: // hlt
EIP = End_of_program;
break;
// our first opcode
case 0x05: { // add imm32 to EAX
int32_t arg2 = imm32();
trace(2, "run") << "add imm32 0x" << HEXWORD << arg2 << " to reg EAX" << end();
BINARY_ARITHMETIC_OP(+, Reg[EAX].i, arg2);
break;
}
// End Single-Byte Opcodes
case 0x0f:
switch(op2 = next()) {
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// End Two-Byte Opcodes Starting With 0f
default:
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cerr << "unrecognized second opcode after 0f: " << HEXBYTE << NUM(op2) << '\n';
exit(1);
}
break;
case 0xf3:
switch(op2 = next()) {
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// End Two-Byte Opcodes Starting With f3
case 0x0f:
switch(op3 = next()) {
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// End Three-Byte Opcodes Starting With f3 0f
default:
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cerr << "unrecognized third opcode after f3 0f: " << HEXBYTE << NUM(op3) << '\n';
exit(1);
}
break;
default:
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cerr << "unrecognized second opcode after f3: " << HEXBYTE << NUM(op2) << '\n';
exit(1);
}
break;
default:
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cerr << "unrecognized opcode: " << HEXBYTE << NUM(op) << '\n';
exit(1);
}
}
void load_program(const string& text_bytes, uint32_t addr) {
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istringstream in(text_bytes);
load_program(in, addr);
}
void load_program(istream& in, uint32_t addr) {
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in >> std::noskipws;
while (has_data(in)) {
char c1 = next_hex_byte(in);
if (c1 == '\0') break;
if (!has_data(in)) {
raise << "input program truncated mid-byte\n" << end();
return;
}
char c2 = next_hex_byte(in);
if (c2 == '\0') {
raise << "input program truncated mid-byte\n" << end();
return;
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}
Mem.at(addr) = to_byte(c1, c2);
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trace(99, "load") << addr << " -> " << HEXBYTE << NUM(Mem.at(addr)) << end();
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addr++;
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if (addr >= Mem.size()) Mem.resize(Mem.size()*2);
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}
End_of_program = addr;
}
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char next_hex_byte(istream& in) {
while (has_data(in)) {
char c = '\0';
in >> c;
if (c == ' ' || c == '\n') continue;
while (c == '#') {
while (has_data(in)) {
in >> c;
if (c == '\n') {
in >> c;
break;
}
}
}
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if (c == '\0') return c;
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if (c >= '0' && c <= '9') return c;
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if (c >= 'a' && c <= 'f') return c;
if (c >= 'A' && c <= 'F') return tolower(c);
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// disallow any non-hex characters, including a '0x' prefix
if (!isspace(c)) {
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raise << "invalid non-hex character " << NUM(c) << "\n" << end();
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break;
}
}
return '\0';
}
uint8_t to_byte(char hex_byte1, char hex_byte2) {
return to_hex_num(hex_byte1)*16 + to_hex_num(hex_byte2);
}
uint8_t to_hex_num(char c) {
if (c >= '0' && c <= '9') return c - '0';
if (c >= 'a' && c <= 'f') return c - 'a' + 10;
assert(false);
return 0;
}
inline uint8_t next() {
return Mem.at(EIP++);
}
// read a 32-bit immediate in little-endian order from the instruction stream
int32_t imm32() {
int32_t result = next();
result |= (next()<<8);
result |= (next()<<16);
result |= (next()<<24);
return result;
}
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string rname(uint8_t r) {
switch (r) {
case 0: return "EAX";
case 1: return "ECX";
case 2: return "EDX";
case 3: return "EBX";
case 4: return "ESP";
case 5: return "EBP";
case 6: return "ESI";
case 7: return "EDI";
default: raise << "invalid register " << r << '\n' << end(); return "";
}
}
:(before "End Includes")
#include <iomanip>
#define HEXBYTE std::hex << std::setw(2) << std::setfill('0')
#define HEXWORD std::hex << std::setw(8) << std::setfill('0')
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// ugly that iostream doesn't print uint8_t as an integer
#define NUM(X) static_cast<int>(X)
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#include <stdint.h>